3.6 \(\int x^2 \cosh (a+b x-c x^2) \, dx\)

Optimal. Leaf size=227 \[ -\frac {\sqrt {\pi } b^2 e^{a+\frac {b^2}{4 c}} \text {erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}-\frac {\sqrt {\pi } e^{a+\frac {b^2}{4 c}} \text {erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {\sqrt {\pi } b^2 e^{-a-\frac {b^2}{4 c}} \text {erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}+\frac {\sqrt {\pi } e^{-a-\frac {b^2}{4 c}} \text {erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c} \]

[Out]

-1/4*b*sinh(-c*x^2+b*x+a)/c^2-1/2*x*sinh(-c*x^2+b*x+a)/c-1/16*b^2*exp(a+1/4*b^2/c)*erf(1/2*(-2*c*x+b)/c^(1/2))
*Pi^(1/2)/c^(5/2)-1/8*exp(a+1/4*b^2/c)*erf(1/2*(-2*c*x+b)/c^(1/2))*Pi^(1/2)/c^(3/2)-1/16*b^2*exp(-a-1/4*b^2/c)
*erfi(1/2*(-2*c*x+b)/c^(1/2))*Pi^(1/2)/c^(5/2)+1/8*exp(-a-1/4*b^2/c)*erfi(1/2*(-2*c*x+b)/c^(1/2))*Pi^(1/2)/c^(
3/2)

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Rubi [A]  time = 0.14, antiderivative size = 227, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 7, integrand size = 16, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.438, Rules used = {5387, 5374, 2234, 2205, 2204, 5383, 5375} \[ -\frac {\sqrt {\pi } b^2 e^{a+\frac {b^2}{4 c}} \text {Erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}-\frac {\sqrt {\pi } e^{a+\frac {b^2}{4 c}} \text {Erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {\sqrt {\pi } b^2 e^{-a-\frac {b^2}{4 c}} \text {Erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}+\frac {\sqrt {\pi } e^{-a-\frac {b^2}{4 c}} \text {Erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c} \]

Antiderivative was successfully verified.

[In]

Int[x^2*Cosh[a + b*x - c*x^2],x]

[Out]

-(b^2*E^(a + b^2/(4*c))*Sqrt[Pi]*Erf[(b - 2*c*x)/(2*Sqrt[c])])/(16*c^(5/2)) - (E^(a + b^2/(4*c))*Sqrt[Pi]*Erf[
(b - 2*c*x)/(2*Sqrt[c])])/(8*c^(3/2)) - (b^2*E^(-a - b^2/(4*c))*Sqrt[Pi]*Erfi[(b - 2*c*x)/(2*Sqrt[c])])/(16*c^
(5/2)) + (E^(-a - b^2/(4*c))*Sqrt[Pi]*Erfi[(b - 2*c*x)/(2*Sqrt[c])])/(8*c^(3/2)) - (b*Sinh[a + b*x - c*x^2])/(
4*c^2) - (x*Sinh[a + b*x - c*x^2])/(2*c)

Rule 2204

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erfi[(c + d*x)*Rt[b*Log[F], 2
]])/(2*d*Rt[b*Log[F], 2]), x] /; FreeQ[{F, a, b, c, d}, x] && PosQ[b]

Rule 2205

Int[(F_)^((a_.) + (b_.)*((c_.) + (d_.)*(x_))^2), x_Symbol] :> Simp[(F^a*Sqrt[Pi]*Erf[(c + d*x)*Rt[-(b*Log[F]),
 2]])/(2*d*Rt[-(b*Log[F]), 2]), x] /; FreeQ[{F, a, b, c, d}, x] && NegQ[b]

Rule 2234

Int[(F_)^((a_.) + (b_.)*(x_) + (c_.)*(x_)^2), x_Symbol] :> Dist[F^(a - b^2/(4*c)), Int[F^((b + 2*c*x)^2/(4*c))
, x], x] /; FreeQ[{F, a, b, c}, x]

Rule 5374

Int[Sinh[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[1/2, Int[E^(a + b*x + c*x^2), x], x] - Dist[1/2
, Int[E^(-a - b*x - c*x^2), x], x] /; FreeQ[{a, b, c}, x]

Rule 5375

Int[Cosh[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2], x_Symbol] :> Dist[1/2, Int[E^(a + b*x + c*x^2), x], x] + Dist[1/2
, Int[E^(-a - b*x - c*x^2), x], x] /; FreeQ[{a, b, c}, x]

Rule 5383

Int[Cosh[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]*((d_.) + (e_.)*(x_)), x_Symbol] :> Simp[(e*Sinh[a + b*x + c*x^2])/
(2*c), x] - Dist[(b*e - 2*c*d)/(2*c), Int[Cosh[a + b*x + c*x^2], x], x] /; FreeQ[{a, b, c, d, e}, x] && NeQ[b*
e - 2*c*d, 0]

Rule 5387

Int[Cosh[(a_.) + (b_.)*(x_) + (c_.)*(x_)^2]*((d_.) + (e_.)*(x_))^(m_), x_Symbol] :> Simp[(e*(d + e*x)^(m - 1)*
Sinh[a + b*x + c*x^2])/(2*c), x] + (-Dist[(e^2*(m - 1))/(2*c), Int[(d + e*x)^(m - 2)*Sinh[a + b*x + c*x^2], x]
, x] - Dist[(b*e - 2*c*d)/(2*c), Int[(d + e*x)^(m - 1)*Cosh[a + b*x + c*x^2], x], x]) /; FreeQ[{a, b, c, d, e}
, x] && GtQ[m, 1] && NeQ[b*e - 2*c*d, 0]

Rubi steps

\begin {align*} \int x^2 \cosh \left (a+b x-c x^2\right ) \, dx &=-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c}+\frac {\int \sinh \left (a+b x-c x^2\right ) \, dx}{2 c}+\frac {b \int x \cosh \left (a+b x-c x^2\right ) \, dx}{2 c}\\ &=-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c}+\frac {b^2 \int \cosh \left (a+b x-c x^2\right ) \, dx}{4 c^2}+\frac {\int e^{a+b x-c x^2} \, dx}{4 c}-\frac {\int e^{-a-b x+c x^2} \, dx}{4 c}\\ &=-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c}+\frac {b^2 \int e^{a+b x-c x^2} \, dx}{8 c^2}+\frac {b^2 \int e^{-a-b x+c x^2} \, dx}{8 c^2}-\frac {e^{-a-\frac {b^2}{4 c}} \int e^{\frac {(-b+2 c x)^2}{4 c}} \, dx}{4 c}+\frac {e^{a+\frac {b^2}{4 c}} \int e^{-\frac {(b-2 c x)^2}{4 c}} \, dx}{4 c}\\ &=-\frac {e^{a+\frac {b^2}{4 c}} \sqrt {\pi } \text {erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}+\frac {e^{-a-\frac {b^2}{4 c}} \sqrt {\pi } \text {erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c}+\frac {\left (b^2 e^{-a-\frac {b^2}{4 c}}\right ) \int e^{\frac {(-b+2 c x)^2}{4 c}} \, dx}{8 c^2}+\frac {\left (b^2 e^{a+\frac {b^2}{4 c}}\right ) \int e^{-\frac {(b-2 c x)^2}{4 c}} \, dx}{8 c^2}\\ &=-\frac {b^2 e^{a+\frac {b^2}{4 c}} \sqrt {\pi } \text {erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}-\frac {e^{a+\frac {b^2}{4 c}} \sqrt {\pi } \text {erf}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {b^2 e^{-a-\frac {b^2}{4 c}} \sqrt {\pi } \text {erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{16 c^{5/2}}+\frac {e^{-a-\frac {b^2}{4 c}} \sqrt {\pi } \text {erfi}\left (\frac {b-2 c x}{2 \sqrt {c}}\right )}{8 c^{3/2}}-\frac {b \sinh \left (a+b x-c x^2\right )}{4 c^2}-\frac {x \sinh \left (a+b x-c x^2\right )}{2 c}\\ \end {align*}

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Mathematica [A]  time = 0.31, size = 152, normalized size = 0.67 \[ \frac {\sqrt {\pi } \left (b^2+2 c\right ) \text {erf}\left (\frac {2 c x-b}{2 \sqrt {c}}\right ) \left (\sinh \left (a+\frac {b^2}{4 c}\right )+\cosh \left (a+\frac {b^2}{4 c}\right )\right )+\sqrt {\pi } \left (b^2-2 c\right ) \text {erfi}\left (\frac {2 c x-b}{2 \sqrt {c}}\right ) \left (\cosh \left (a+\frac {b^2}{4 c}\right )-\sinh \left (a+\frac {b^2}{4 c}\right )\right )-4 \sqrt {c} (b+2 c x) \sinh (a+x (b-c x))}{16 c^{5/2}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^2*Cosh[a + b*x - c*x^2],x]

[Out]

((b^2 - 2*c)*Sqrt[Pi]*Erfi[(-b + 2*c*x)/(2*Sqrt[c])]*(Cosh[a + b^2/(4*c)] - Sinh[a + b^2/(4*c)]) + (b^2 + 2*c)
*Sqrt[Pi]*Erf[(-b + 2*c*x)/(2*Sqrt[c])]*(Cosh[a + b^2/(4*c)] + Sinh[a + b^2/(4*c)]) - 4*Sqrt[c]*(b + 2*c*x)*Si
nh[a + x*(b - c*x)])/(16*c^(5/2))

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fricas [B]  time = 0.77, size = 466, normalized size = 2.05 \[ -\frac {4 \, c^{2} x - 2 \, {\left (2 \, c^{2} x + b c\right )} \cosh \left (c x^{2} - b x - a\right )^{2} + \sqrt {\pi } {\left ({\left (b^{2} - 2 \, c\right )} \cosh \left (c x^{2} - b x - a\right ) \cosh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) - {\left (b^{2} - 2 \, c\right )} \cosh \left (c x^{2} - b x - a\right ) \sinh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) + {\left ({\left (b^{2} - 2 \, c\right )} \cosh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) - {\left (b^{2} - 2 \, c\right )} \sinh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right )\right )} \sinh \left (c x^{2} - b x - a\right )\right )} \sqrt {-c} \operatorname {erf}\left (\frac {{\left (2 \, c x - b\right )} \sqrt {-c}}{2 \, c}\right ) - \sqrt {\pi } {\left ({\left (b^{2} + 2 \, c\right )} \cosh \left (c x^{2} - b x - a\right ) \cosh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) + {\left (b^{2} + 2 \, c\right )} \cosh \left (c x^{2} - b x - a\right ) \sinh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) + {\left ({\left (b^{2} + 2 \, c\right )} \cosh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right ) + {\left (b^{2} + 2 \, c\right )} \sinh \left (\frac {b^{2} + 4 \, a c}{4 \, c}\right )\right )} \sinh \left (c x^{2} - b x - a\right )\right )} \sqrt {c} \operatorname {erf}\left (\frac {2 \, c x - b}{2 \, \sqrt {c}}\right ) - 4 \, {\left (2 \, c^{2} x + b c\right )} \cosh \left (c x^{2} - b x - a\right ) \sinh \left (c x^{2} - b x - a\right ) - 2 \, {\left (2 \, c^{2} x + b c\right )} \sinh \left (c x^{2} - b x - a\right )^{2} + 2 \, b c}{16 \, {\left (c^{3} \cosh \left (c x^{2} - b x - a\right ) + c^{3} \sinh \left (c x^{2} - b x - a\right )\right )}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*cosh(-c*x^2+b*x+a),x, algorithm="fricas")

[Out]

-1/16*(4*c^2*x - 2*(2*c^2*x + b*c)*cosh(c*x^2 - b*x - a)^2 + sqrt(pi)*((b^2 - 2*c)*cosh(c*x^2 - b*x - a)*cosh(
1/4*(b^2 + 4*a*c)/c) - (b^2 - 2*c)*cosh(c*x^2 - b*x - a)*sinh(1/4*(b^2 + 4*a*c)/c) + ((b^2 - 2*c)*cosh(1/4*(b^
2 + 4*a*c)/c) - (b^2 - 2*c)*sinh(1/4*(b^2 + 4*a*c)/c))*sinh(c*x^2 - b*x - a))*sqrt(-c)*erf(1/2*(2*c*x - b)*sqr
t(-c)/c) - sqrt(pi)*((b^2 + 2*c)*cosh(c*x^2 - b*x - a)*cosh(1/4*(b^2 + 4*a*c)/c) + (b^2 + 2*c)*cosh(c*x^2 - b*
x - a)*sinh(1/4*(b^2 + 4*a*c)/c) + ((b^2 + 2*c)*cosh(1/4*(b^2 + 4*a*c)/c) + (b^2 + 2*c)*sinh(1/4*(b^2 + 4*a*c)
/c))*sinh(c*x^2 - b*x - a))*sqrt(c)*erf(1/2*(2*c*x - b)/sqrt(c)) - 4*(2*c^2*x + b*c)*cosh(c*x^2 - b*x - a)*sin
h(c*x^2 - b*x - a) - 2*(2*c^2*x + b*c)*sinh(c*x^2 - b*x - a)^2 + 2*b*c)/(c^3*cosh(c*x^2 - b*x - a) + c^3*sinh(
c*x^2 - b*x - a))

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giac [A]  time = 0.13, size = 167, normalized size = 0.74 \[ -\frac {\frac {\sqrt {\pi } {\left (b^{2} + 2 \, c\right )} \operatorname {erf}\left (-\frac {1}{2} \, \sqrt {c} {\left (2 \, x - \frac {b}{c}\right )}\right ) e^{\left (\frac {b^{2} + 4 \, a c}{4 \, c}\right )}}{\sqrt {c}} + 2 \, {\left (c {\left (2 \, x - \frac {b}{c}\right )} + 2 \, b\right )} e^{\left (-c x^{2} + b x + a\right )}}{16 \, c^{2}} - \frac {\frac {\sqrt {\pi } {\left (b^{2} - 2 \, c\right )} \operatorname {erf}\left (-\frac {1}{2} \, \sqrt {-c} {\left (2 \, x - \frac {b}{c}\right )}\right ) e^{\left (-\frac {b^{2} + 4 \, a c}{4 \, c}\right )}}{\sqrt {-c}} - 2 \, {\left (c {\left (2 \, x - \frac {b}{c}\right )} + 2 \, b\right )} e^{\left (c x^{2} - b x - a\right )}}{16 \, c^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*cosh(-c*x^2+b*x+a),x, algorithm="giac")

[Out]

-1/16*(sqrt(pi)*(b^2 + 2*c)*erf(-1/2*sqrt(c)*(2*x - b/c))*e^(1/4*(b^2 + 4*a*c)/c)/sqrt(c) + 2*(c*(2*x - b/c) +
 2*b)*e^(-c*x^2 + b*x + a))/c^2 - 1/16*(sqrt(pi)*(b^2 - 2*c)*erf(-1/2*sqrt(-c)*(2*x - b/c))*e^(-1/4*(b^2 + 4*a
*c)/c)/sqrt(-c) - 2*(c*(2*x - b/c) + 2*b)*e^(c*x^2 - b*x - a))/c^2

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maple [A]  time = 0.12, size = 244, normalized size = 1.07 \[ \frac {x \,{\mathrm e}^{c \,x^{2}-b x -a}}{4 c}+\frac {b \,{\mathrm e}^{c \,x^{2}-b x -a}}{8 c^{2}}+\frac {b^{2} \sqrt {\pi }\, {\mathrm e}^{-\frac {4 a c +b^{2}}{4 c}} \erf \left (\sqrt {-c}\, x +\frac {b}{2 \sqrt {-c}}\right )}{16 c^{2} \sqrt {-c}}-\frac {\sqrt {\pi }\, {\mathrm e}^{-\frac {4 a c +b^{2}}{4 c}} \erf \left (\sqrt {-c}\, x +\frac {b}{2 \sqrt {-c}}\right )}{8 c \sqrt {-c}}-\frac {x \,{\mathrm e}^{-c \,x^{2}+b x +a}}{4 c}-\frac {b \,{\mathrm e}^{-c \,x^{2}+b x +a}}{8 c^{2}}-\frac {b^{2} \sqrt {\pi }\, {\mathrm e}^{\frac {4 a c +b^{2}}{4 c}} \erf \left (-\sqrt {c}\, x +\frac {b}{2 \sqrt {c}}\right )}{16 c^{\frac {5}{2}}}-\frac {\sqrt {\pi }\, {\mathrm e}^{\frac {4 a c +b^{2}}{4 c}} \erf \left (-\sqrt {c}\, x +\frac {b}{2 \sqrt {c}}\right )}{8 c^{\frac {3}{2}}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*cosh(-c*x^2+b*x+a),x)

[Out]

1/4/c*x*exp(c*x^2-b*x-a)+1/8*b/c^2*exp(c*x^2-b*x-a)+1/16*b^2/c^2*Pi^(1/2)*exp(-1/4*(4*a*c+b^2)/c)/(-c)^(1/2)*e
rf((-c)^(1/2)*x+1/2*b/(-c)^(1/2))-1/8/c*Pi^(1/2)*exp(-1/4*(4*a*c+b^2)/c)/(-c)^(1/2)*erf((-c)^(1/2)*x+1/2*b/(-c
)^(1/2))-1/4/c*x*exp(-c*x^2+b*x+a)-1/8*b/c^2*exp(-c*x^2+b*x+a)-1/16*b^2/c^(5/2)*Pi^(1/2)*exp(1/4*(4*a*c+b^2)/c
)*erf(-c^(1/2)*x+1/2*b/c^(1/2))-1/8/c^(3/2)*Pi^(1/2)*exp(1/4*(4*a*c+b^2)/c)*erf(-c^(1/2)*x+1/2*b/c^(1/2))

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maxima [B]  time = 0.66, size = 834, normalized size = 3.67 \[ \text {result too large to display} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^2*cosh(-c*x^2+b*x+a),x, algorithm="maxima")

[Out]

1/3*x^3*cosh(c*x^2 - b*x - a) - 1/96*(sqrt(pi)*(2*c*x - b)*b^3*(erf(1/2*sqrt((2*c*x - b)^2/c)) - 1)/(sqrt((2*c
*x - b)^2/c)*(-c)^(7/2)) - 6*b^2*c*e^(-1/4*(2*c*x - b)^2/c)/(-c)^(7/2) - 12*(2*c*x - b)^3*b*gamma(3/2, 1/4*(2*
c*x - b)^2/c)/(((2*c*x - b)^2/c)^(3/2)*(-c)^(7/2)) - 8*c^2*gamma(2, 1/4*(2*c*x - b)^2/c)/(-c)^(7/2))*b*e^(a +
1/4*b^2/c)/sqrt(-c) - 1/96*(sqrt(pi)*(2*c*x - b)*b^4*(erf(1/2*sqrt((2*c*x - b)^2/c)) - 1)/(sqrt((2*c*x - b)^2/
c)*(-c)^(9/2)) - 8*b^3*c*e^(-1/4*(2*c*x - b)^2/c)/(-c)^(9/2) - 24*(2*c*x - b)^3*b^2*gamma(3/2, 1/4*(2*c*x - b)
^2/c)/(((2*c*x - b)^2/c)^(3/2)*(-c)^(9/2)) - 32*b*c^2*gamma(2, 1/4*(2*c*x - b)^2/c)/(-c)^(9/2) - 16*(2*c*x - b
)^5*gamma(5/2, 1/4*(2*c*x - b)^2/c)/(((2*c*x - b)^2/c)^(5/2)*(-c)^(9/2)))*c*e^(a + 1/4*b^2/c)/sqrt(-c) + 1/96*
(sqrt(pi)*(2*c*x - b)*b^3*(erf(1/2*sqrt(-(2*c*x - b)^2/c)) - 1)/(sqrt(-(2*c*x - b)^2/c)*c^(7/2)) + 6*b^2*e^(1/
4*(2*c*x - b)^2/c)/c^(5/2) - 12*(2*c*x - b)^3*b*gamma(3/2, -1/4*(2*c*x - b)^2/c)/((-(2*c*x - b)^2/c)^(3/2)*c^(
7/2)) - 8*gamma(2, -1/4*(2*c*x - b)^2/c)/c^(3/2))*b*e^(-a - 1/4*b^2/c)/sqrt(c) - 1/96*(sqrt(pi)*(2*c*x - b)*b^
4*(erf(1/2*sqrt(-(2*c*x - b)^2/c)) - 1)/(sqrt(-(2*c*x - b)^2/c)*c^(9/2)) + 8*b^3*e^(1/4*(2*c*x - b)^2/c)/c^(7/
2) - 24*(2*c*x - b)^3*b^2*gamma(3/2, -1/4*(2*c*x - b)^2/c)/((-(2*c*x - b)^2/c)^(3/2)*c^(9/2)) - 32*b*gamma(2,
-1/4*(2*c*x - b)^2/c)/c^(5/2) - 16*(2*c*x - b)^5*gamma(5/2, -1/4*(2*c*x - b)^2/c)/((-(2*c*x - b)^2/c)^(5/2)*c^
(9/2)))*sqrt(c)*e^(-a - 1/4*b^2/c)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.00 \[ \int x^2\,\mathrm {cosh}\left (-c\,x^2+b\,x+a\right ) \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^2*cosh(a + b*x - c*x^2),x)

[Out]

int(x^2*cosh(a + b*x - c*x^2), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int x^{2} \cosh {\left (a + b x - c x^{2} \right )}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**2*cosh(-c*x**2+b*x+a),x)

[Out]

Integral(x**2*cosh(a + b*x - c*x**2), x)

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